How many tickets of each type were sold? = Number Labels. The number of adult tickets sold was 100 less than 3 times the number of student tickets. Total income from the sale of tickets was $550. let 2a = let 1.50s =ĩ Example 3 Admission to the play was $2 for an adult and $1Įxample 3 Admission to the play was $2 for an adult and $1.50 for a student. let a = # of adult tickets let s = # of student tickets value of adult tickets value of student tickets Value Labels. How many tickets of each type were sold? Number Labels. The width is 5 m and the length is 14 m.Ĩ Example 3 Admission to the play was $2 for an adult and $1Įxample 3 Admission to the play was $2 for an adult and $1.50 for a student. let w = width let l = length width width length 2. If the perimeter is 38 m, find the dimensions. g + b = 25 2g = 3b There are 15 girls and 10 boys in the class.ħ Example 2 The length of a rectangle is 4 m more than twice its widthĮxample 2 The length of a rectangle is 4 m more than twice its width. Let g = # of girls Let b = # of boys Write an equation for each of the first two sentences. Choose a different variable for each type of person. How many boys and girls are there in the class? Assign Labels. Twice the number of girls is equal to 3 times the number of boys. = length let l = length let w = width width width length Formula The width is 18 m and the length is 37 m.Ħ Example 1 A class has a total of 25 studentsĮxample 1 A class has a total of 25 students. If the perimeter is 110 m, find the dimensions. The length of a rectangle is 1 m more than twice its width. Jose is 3 and Meg is 15.ĥ The length of a rectangle is 1 m more than twice its width m = 5j m + j = 18 Solve the system of equations. Let m = Meg’s age Let j = Jose’s age Write an equation for each of the first two sentences. Choose a different variable for each person. 5) Write a sentence and check your solution in the word problem.Ĥ Meg’s age is 5 times Jose’s age. (Translate from sentences) 3) Write two algebraic models (equations). Elimination Using Multiplication –can be applied to create opposites in any system.ģ Solving Word Problems Using A Linear Systemġ) Write two sets of labels, if necessary (one set for number, one set for value, weight etc.) 2) Write two verbal models. Elimination Using Subtraction –convenient if one of the variables has the same coefficient in the two equations. Elimination Using Addition –convenient when a variable appears in different equations with coefficients that are opposites. It is especially convenient when one of the variables has a coefficient of 1 or –1. Substitution – requires that one of the variables be isolated on one side of the equation. Graphing – can provide a useful method for estimating a solution and to provide a visual model of the problem. Presentation on theme: "Linear Systems and Problem Solving"- Presentation transcript:Ģ Ways to Solve a System of Linear Equations
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